![]() That side is opposite of this 30 degrees, so I can say that it's That's perpendicular, I can write as well let's So it's only thisĬomponent of the 10 newtons that's going to contribute In other words, only perpendicularĬomponents of the force, that is perpendicular to the Perpendicular to this R vector in order to get the door to rotate. Pull the door that way is not gonna cause this door to rotate. You'd think I was crazy 'cause that's not gonnaĬause the door to rotate. Open this revolving glass door by pushing that way, This is the way you push onĪ door to make it rotate. Gonna cause this door to rotate, is this perpendicular component. So the only component of this force, of this 10 newtons that is Something to start rotating, or to change its rotation. ![]() ![]() Is gonna exert a torque, and that should make sense. This component as well, this perpendicular component, and I'll call that F perpendicular 'cause this component is Up into a component that goes this way, I'llĬall that F parallel because that force is parallel to R. R doesn't exert any torque, and that should make sense. So only the perpendicularĬomponent of this force is gonna exert a torque on the door. If you just write thisįormula for torque like this, what you really mean is that this force is the perpendicular force to this R. The R here is two meters, so my torque should just be 20, right? Two times 10? But that's not right 'cause this force is not representing the Made is to say just well, the force was 10 newtons, Now we can solve for this torque, but you have to be careful. Let's say this happened toīe two meters from this axis to the point where thisġ0 newtons was applied. The direction is not toward the axis, the direction is always awayįrom the axis to that point where the force happens toīe applied to the object. You can think of it as a position vector, but regardless it points from the axis to the point where the force is applied. Point where the force is applied and technically this R is a vector. Note that R is not theĮntire radius necessarily, and it's not the entire So in this case, that would represent from this axis right here to the point where the force was applied would be this. Is that this R represents the vector that pointsįrom the axis to the point where the force was applied. Here is I'd just say, alright torque, I know what torque is. Now the first thing I might try to figure out the torque The axis, we could figure out how much torque we're exerting. It'd be really hard to openĪ door right near the hinge. So a force out here wouldĪpply much more torque than a force right here. But the farther out you apply this force, the more torque you will get for the amount of force In other words, if you go try to push open this revolving glassĭoor at the very center, nothing's gonna happenīecause it's not gonna rotate. It has to be applied at some point besides the axis. Know because if a force is gonna exert a torque, Regardless, let's say theĪxis was in the very center, and that's crucial to ![]() Revolving glass doors at the nice restaurants and hotels. With a nail through it, or maybe this is a bird's eye view of one of those fancy To us that in this problem the object, whatever it is, Now one of the first things you want to do when finding the torque Let's figure out how to find the torque from say this 10 newton force exerted at this angle of 30 degrees. I got most anxious about were these problems where theįorce was at a weird angle, so let's do this. There are conceptual waysĪnd tricks to figure it out, so I want to share those with you so that going forward weĭon't have to be so anxious when we're solving a torque problem. This video is show you how to find the torque. Used to give me anxiety, and I think it was because Iĭidn't really understand well what torque meant or how to find it. I don't know about you, but torque problems
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